What is the pressure (in atm) of 5.46 mol of gas in a 37.1 L container at 485 K?
What is the pressure (in atm) of 5.46 mol of gas in a 37.1 L container...
Hint: % difference = 100×(P ideal - Pvan der Waals) / P idealAccording to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Ar gas, a =1.345L2 atm/mol2 and b = 3.219×10-2 L/mol.
What is the pressure of a 5 L container that has 5.1 mol of a gas at 591 K?
1.Ideal Gas Law PV = nRT with atm: R = 0.0821 L*atm/(K*mol) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? 2. If I contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container? 3. If I have 7.7 moles of gas at a pressure of 0.09...
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
A 10.74 mol sample of oxygen gas is maintained in a 0.8354 L container at 296.1 K. What is the pressure in atm calculated using the van der Waals' equation for O2 gas under these conditions? For 02, a = 1.360 Latm/mo12 and b = 3.183x10-2 L/mol. atm
A 9.450 mol sample of krypton gas is maintained in a 0.8100 L container at 300.1 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol. atm
If 3.05 mol of a gas has a volume of 43.3 L and a pressure of 1.55 atm, what is the temperature? Use R= 0.0821 atm. L/mol K. K
R = 0.08206 (L x atm)/(K x mol) 1. What is the pressure in a 580 mL container that has 0.545 moles of oxygen gas at 32.0 °C?
A 9.083 mol sample of methane gas is maintained in a 0.8377 L container at 304.9 K. What is the pressure in atm calculated using the van der Waals' equation for CH4 gas under these conditions? For CH4, a = 2.253 L^2atm/mol^2 and b = 4.278 x 10^-2 L/mol.
At 273 K, 1.00 mol of an ideal gas confined to a 2.00-L container exerts a pressure of 11.2 atm. Under the same conditions, what pressure is exerted by CO2, for which a = 3.59 L2 atm mol-2 and b = 0.0427 L mol-1 0 -0.90 10.5 09.1 O 7.2 11.4