Question

If 3.05 mol of a gas has a volume of 43.3 L and a pressure of 1.55 atm, what is the temperature? Use R= 0.0821 atm. L/mol K. K

Answer 1

Step 1: Explanation:

We know the ideal gas equation, PV=nRT

where, R=universal gas constant, T=temperature , P=pressure, V=volume, n=moles.

hence, the equation becomes

=====> PV=nRT

or ,   PV= nRT

or, T= PV / nR

Step 2: Calculate the Temperature

Given,

Pressure(P) = 1.55 atm

Mole(n) = 3.05 mol

Volume(V) = 43.3 L

substitute the above value in equation

  T= PV / nR

T= ( 1.55 atm x 43.3 L / 3.05 mol x 0.0821 L.atm / mol.K ) = 268 K