How many grams of solid sodium hydroxide are required to make 500.00 mL of a 0.07 M NaOH solution?
Answer with two decimal places.
concentration = 0.07 M
volume = 500 ml = 0.5 L
no of moles = concentration * volume
= 0.07 M * 0.5 L
= 0.035 mol
now mass = molar mass * no of moles
grams of solid sodium hydroxide are required = 0.035 mol * 40 g/mol
= 1.4 g
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