Al(OH)3 + 3 H+ <--> Al3+ + 3 H2O You find that the solution pH =...

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Al(OH)3 + 3 H+ <--> Al3+ + 3 H2O You find that the solution pH =...

Al(OH)3 + 3 H+ <--> Al3+ + 3 H2O

You find that the solution pH = 5, and that [Al3+] = 10-2 mol/L. Assuming the activity coefficient = 1 for Al3+, what is the log(Keq) of the Al(OH)3 dissolution written above assuming the system is at equilibrium? If you got stuck on a, assume that log(Al3+)=log(Keq)-3pH + 30.

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