a 50 mM buffer of monosodium dihydrogen phosphate and disodium monohydrogen phosphate at pH 7. The relevant pKa is 6.8. You'll have to figure out the concentrations of all the ionic species before computing the ionic strength.
-Solve the problem using the Henderson-Hasselbalch equation to
find the concentrations, use the two equations with two unknowns to
solve.
HPO4 = 0.031M, and H2PO4=0.019M. Then do the ionic strength.
It's supposed to be u=0.096M, but I don't
understand how this works. I'm looking for an detailed answer.
a 50 mM buffer of monosodium dihydrogen phosphate and disodium monohydrogen phosphate at pH 7. The...
Calculate the concentration of disodium phosphate (Na2HPO4) and monosodium phosphate (NaH2PO4) to prepare of 100.0mM buffer at pH 7.50. the pKa of H2PO4= 7.21
The Henderson-Hasselbalch equation relates the pH of a buffer solution to the pKa of its conjugate acid and the ratio of the concentrations of the conjugate base and acid. The equation is important in laboratory work that makes use of buffered solutions, in industrial processes where pH needs to be controlled, and in medicine, where understanding the Henderson-Hasselbalch equation is critical for the control of blood pH. Part A As a technician in a large pharmaceutical research firm, you need...
Henderson-Hasselbach equation: pH- pKa log (IA-|/IHA]) 1. Phosphate buffer is a mixture of KH2PO4 and K2HPO4. Note that KH2PO4 has one additional proton. The pKa of the acid is 6.8. Use the Henderson-Hasselbach equation (above) to calculate the ratio of [K2HPO41[KH2PO4] needed to make a solution that is pH 7.2 2. To make a solution that is 0.2 M phosphate, the concentration of KH2PO4 and K2HPO4 must add up to 0.2 M. Use the ratio you calculated above, and the...
A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 mL solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O,. The initial concentration of both the acid and the base are 0.0100 mol/ 0.1000 L...