sample standard deviation
x̅ = 4.7
From the given data we can calculate sample standard deviation s = 2.32
Sampling error = s/√n = 2.32/√14 = 0.62
An internet service provider states that the average number of hours its customers are online each...
An Internet service provider states that the average number of hours its customers are online each day is 4.08. Suppose a random sample of 14 of the company's customers is selected and the average number of hours that they are online each day is measured. The sample results are shown in the accompanying table. 5.76 6.08 4.26 5.85 6.82 1.77 7.66 5.11 3.89 2.67 6.89 6.68 3.58 1.12 Based on the sample of 14 customers, how much sampling error exists?...
A survey is carried out to study the number of hours, X, per day spent on using the Internet by the customers of an Internet Service Provider (ISP). Responses from 15 randomly selected customers give the following data:3 2 5 6 1 5 3 4 5 2 4 5 9 5 1(a) Determine the mean and variance of the data set. (b) Is there an outlier in the data set? Justify your answer. (c) Suppose a selected customer is found to spend...
1. Two manufacturing processes are being compared to try to reduce the number of defective products made. During 8 shifts for each process, the following results were observed: Line A Line B n 181 | 187 Based on a 5% significance level, did line B have a larger average than line A? *Use the tables I gave you in the handouts for the critical values *Use the appropriate test statistic value, NOT the p-value method *Use and show the 5...