Write a C program to find out the number of ordered pairs (a,b) of positive integers, such that: 1/a + 1/b = 3/2018.
Code:
#include "bits/stdc++.h"
using namespace std;
// used long long int to counter overflow
// function to return value of the experession
2018*b/(3*b-2018)
long double value(long long int b){
return (long double)(2018*b)/(3*b-2018);
}
signed main(){
long long int bl = 673 , br = 1358114;
long long int ans = 0;
// loop over every possible value of b
for(long long int b = bl;b<=br;b++)
// if the value of a is a interger ans++
if((long long int)value(b) == value(b)) ans++;
cout<<ans<<endl;
}
Write a C program to find out the number of ordered pairs (a,b) of positive integers,...
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