(1 point) The gender and enrollment status of one-hundred students is summarized in the table below....
(1 point) The gender and enrollment status of one-hundred students is summarized in the table below.
| Female | Male | Total | |
| Part-time | 2323 | 2828 | 51 |
| Full-time | 1313 | 3636 | 4949 |
| Total | 3636 | 6464 | 100100 |
If a student is selected at random from those surveyed, find the
probability of each of the following events.
1. The student is female or is enrolled
part-time.
Answer:
2. The student is male or is enrolled
full-time.
Answer:
3. The student is female or is enrolled
full-time.
Answer:
Homework Answers
Solution :
From given table,
1)
P(female or Part-time)
P(female) + P(Part-time) - P(female or Part-time)
= (36 + 51 - 23) / 100
= 64 / 100
= 0.64
2)
P(male or Part-time)
= (64 + 51 - 28) / 100
= 87 / 100
= .87
3)
P(female or Full-time)
= (36 + 49 - 13) / 100
= 72 / 100
= 0.72
Add Answer to:
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