Question

The Law of Or

The chances of one event OR another event occurring = the sum of the chances of each event separately.

Let's call the first event E1, and the second event E2. In this case, let's make E1 the probabilty of winning the toaster, and E2 the probability of winning the washer-dryer. We can now abbreviate these P(E1) and P(E2) for the probability of event 1, and the probability of event 2.

If the game show runs another contest where you can win the prize by picking a ticket out of a hat and your chances of winning are listed in the table below. The probabilities in this problem are given as percentages. That means if the hat contains one hundred pieces of paper in it, then it will have 10 pieces of paper labeled "toaster", 9 pieces of paper labeled "washer-dryer", 1 pieces of paper labeled "vacation" and 80 pieces of paper labeled "pet rock".

If the game show ran the contest again using the following probabilities, what would be the chances of winning any prize other than the tropical vacation?

Prize	Probability
Toaster	10%
Washer-dryer	9%
Vacation	1%
Pet rock	80%

Report answer as a percent, not as a decimal. In other words, if it's 55%, report it as 55, not 0.55

thank you

Answer 1

Answer 2

To find the chances of winning any prize other than the tropical vacation, we need to calculate the sum of the probabilities of winning the toaster, washer-dryer, and pet rock. Here's the calculation:

Chances of winning any prize other than vacation = P(Toaster) + P(Washer-dryer) + P(Pet rock)

Given the probabilities:

P(Toaster) = 10% P(Washer-dryer) = 9% P(Vacation) = 1% P(Pet rock) = 80%

Chances of winning any prize other than vacation = 10% + 9% + 80% = 99%

Therefore, the chances of winning any prize other than the tropical vacation would be 99%.