X ~ Poisson ( )
Where mean = 2
P(X) = e-X / X!
a)
P (X = 0) = e-2 20 / 0!
= 0.1353
b)
P (X = 5) = e-2 25 / 5!
= 0.0361
The number of errors in Abel’s presentations has a mean of 2 per page. The moderator...
The mean number of errors per page made by a member of the word processing pool for a large company is thought to be 1.8 with the number of errors distributed according to a Poisson distribution. If a page is examined, what is the probability that more than two errors will be observed? The probability that more than two errors will be observed is ___________?
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