Assume that a procedure yields a binomial distribution with a
trial repeated n=5n=5 times. Find the probability distribution
given the probability p=0.614p=0.614 of success on a single trial.
Report answers accurate to 4 decimal places.
k | P(X = k) |
---|---|
0 | |
1 | .0682 |
2 | |
3 | |
4 | .2743 |
5 | .0872 |
2.)
Suppose that 65% of all voters prefer Candidate A.
If 10 people are chosen at random for a poll, what is the
probability that exactly 3 of them favor Candidate A?
1) p = 0.614, n = 5
Binomial distribution using excel:
k | Formula | P(X = k) |
0 | = BINOM.DIST(0, 5, 0.614, FALSE) | 0.0086 |
1 | = BINOM.DIST(1, 5, 0.614, FALSE) | 0.0682 |
2 | = BINOM.DIST(2, 5, 0.614, FALSE) | 0.2168 |
3 | = BINOM.DIST(3, 5, 0.614, FALSE) | 0.3449 |
4 | = BINOM.DIST(4, 5, 0.614, FALSE) | 0.2743 |
5 | = BINOM.DIST(5, 5, 0.614, FALSE) | 0.0873 |
-----------------------------------------------------------------------------------
2) Probability of voter that prefer candidate A = 0.65
n = 10
Probability that exactly 3 of them favor Candidate A, P(X=3) =
Using Binomial distribution in excel:
= BINOM.DIST(3, 10, 0.65, FALSE)
= 0.0212
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