At 1000 K, a sample of pure NO2 gas decomposes:
2NO2(g) ⇌ 2NO(g) + O2(g)
The equilibrium constant, KP, is 158. Analysis shows that the partial pressure of O2 is 0.11 atm at equilibrium. Calculate the pressure of NO and NO2 in the mixture.
Pressure of NO:
__atm
Pressure of NO2:
__atm
-------------- 2NO2(g) ⇌ 2NO(g) + O2(g)
I--------------- P ---------------- 0 ------------- 0
C-------------- -2x --------------- +2x ------------ +x
E------------ P-2x -------------- 2x -------------- x
at equilibrium partial pressure of O2 PO2 = x = 0.11atm
at equilibrium partial pressure of O2 PNO = 2x = 2*0.11 = 0.22atm
Kp = P^2NO*PO2/P^2NO2
158 = (0.22)^2*0.11/P^2NO2
P^2NO2 = (0.22)^2*0.11/158
P2NO2 = 3.37*10^-5
PNO2 = 0.0058atm
At 1000 K, a sample of pure NO2 gas decomposes: 2NO2(g) ⇌ 2NO(g) + O2(g) The...
15.58 At 1000 K, a sample of pure NO2 gas decomposes. 2NO2(g) = 2NO(g) + O2(g) The equilibrium constant Kp is 158. Analysis shows that the partial pressure of O2 is 0.25 atm at equilibrium. Calculate the pressure of NO and NO2 in the mixture.
A sample of pure NO2 is heated to 336 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.525 g/L at 0.745 atm . Calculate Kc for the reaction.
(a) For the reaction 2NO2 (g) 2NO (g) + 02 (g) K # 0.50. Predict the direction in which the system will move to reach equilibrium if the initial gas pressures are NO: 0.20 atm . NO2: 0.20 atm (answer: to the right because Q< K) .NO2: 0.0961 atm 02: 0.0589 atm NO: 0.280 atm (answer: the system is already at equilibrium because Q -K) O2: 0.20 atm NO: 0.56 atm NO2: 0.20 atm (answer: to the left because Q>...
If one starts with pure NO2(g) at a pressure of 0.422 atm, the total pressure inside the reaction vessel when 2NO2(g) ? 2NO(g) + O2(g) reaches equilibrium is 0.606 atm. Calculate the equilibrium partial pressure of NO2. Round your answer to three significant figures.
7. Gas Law Problem Nitric oxide (NO) reacts with molecular oxygen 2NO(g) + O2(g) → 2NO2(g). Initially, equal volumes of the reactant gases are separated in a 2.0 L container. The pressure of the NO is 1.25 atm, while the pressure of the O2 is 0.85 atm. What are the partial pressures of the gases once the reaction has gone to completion. Assume the temperature remains constant at 0°C.
Be sure to answer all parts. A) Nitrogen dioxide decomposes according to the reaction 2 NO2(g) ⇌ 2 NO(g) + O2(g) where Kp = 4.48 × 10−13 at a certain temperature. If 0.85 atm of NO2 is added to a container and allowed to come to equilibrium, what are the equilibrium partial pressures of NO(g) and O2(g)? ___atm O2 ___atm NO B) For the following reaction, Kp = 0.262 at 1000°C: C(s) + 2H2(g) ⇌ CH4(g) At equilibrium, the partial...
Consider the following reaction: 2NO(g)+O2(g)⇌2NO2(g)2NO(g)+O2(g)⇌2NO2(g) The data in the table show the equilibrium constant for this reaction measured at several different temperatures. Temperature K 400 1.9x10^7 425 2.5x10^6 465 1.6x10^5 515 8.8x10^3 600 2.0x10^2 Use the data to find ΔrS∘ΔrS∘ for the reaction. (answer in J K-1 mol-1) The answer is NOT 158
Answer is A 47. The oxidation of nitric oxide to nitrogen dioxide is 2NO(g) + O2(g) + 2NO2(g) If 100.0 mL of NO (at STP) reacts with 400.0 mL of O2 at STP, calculate the partial pressure of NO2 in the final reaction mixture. A) 0.222 atm B) 0.333 atm C) 0.286 atm 0.250 atm E) 1.00 atm
Calculate ΔS∘rxn for the reaction 2NO(g)+O2(g)→2NO2(g) Substance S∘ (J/mol⋅K) NO2 240.0 O2 205.2 NO 210.8
For the reaction 2NO(g) + O2(g) —>2NO2(g) AH° = -114.2 kJ and AS° = -146.5 J/K The equilibrium constant for this reaction at 270.0 K is Assume that AH° and AS are independent of temperature. Submit Answer Try Another Version 3 item attempts remaining elefchces to access important values if needed for this question, Consider the reaction 2CO2(g) + 5H2(g)CH2(g) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, calculate AG for this reaction at 298.15K if...