A disk, initially rotating at 123 rad/s, is slowed down with a constant angular acceleration of magnitude 3.96 rad/s2. (a) How much time does the disk take to stop? (b) Through what angle (rad) does the disk rotate during that time?
initial = 123 rad/sec
= -3.96 rad/sec2sec2
Using,
= initial + t
0 = 123 - 3.96t
t = 31.06 seconds to stop the disk
(B) using ,
= initial t + 0.5 t2
= (123×31.06) - 0.5 (3.96)(31.06)2
= 3820.38 - 1910.1527
= 1910.22 rad
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