Practice 2)
a) Find the force on a straight conductor of length 30 cm carrying a current of 5A in the –az direction through a field B=0.0035ax - 0.0035ay (Wb/m2 ) (ans: -5.25ax – 5.25ay mN)
b) A 18nC point charge has a velocity of 5x106 m/s in the direction (0.60ax + 0.75ay + 0.3az). Determine the force exerted on the charge by the field: i) B= -3ax + 4ay + 6az (mWb/m2 ) (ans: F= 297ax -405ay + 418.5az N) ii) E= -3ax + 4ay + 6az (kV/m) (ans: F= -54ax + 72ay + 108az N)
Practice 2) a) Find the force on a straight conductor of length 30 cm carrying a...
Q- A conductor of length (L) carrying current of magnitude (i) is placed in a magnetic field of strength (B), experiences a magnetic force, F. If the conductor is oriented in a such a way that the angle between the magnetic field and the wire is (ɸ). A) State the relationship between ɸ, i, F, B and L B) If F=2 N, i=20A, B=150mT, and the length of the conductor is 135cm, What is the angle between the conductor and...
7. Given an infinitely long straight wire carrying a current I, in the +Z direction. Find the net force and the net torque (magnitudes) exerted on a square loop of wire of side a carrying a current I2, whose center is a distance d-a'2 away from the wire if (a.) (12 pts) the straight wire lies in the plane of the loop Side view Ans. orce Ans (Torque) the straight wire is moved directly above the center of the loop...
A straight wire of length / carrying current / crosses a region of the space with uniform magnetie field B. The force exerted on the wire is F. Find the angle between the wire and the force mies of the magnetic field. A doughnut coil of a square cross-section has two windings with numbers of turns Ni and N2 made one on top of another. The inner and outer radiuses of the doughnut are a and b, respectively. Find the...
Find the magnetic force vector on a 2 m segment of straight wire carrying a current of 1/2 A in the z-direction through a uniform magnetic field of 80 mT going in the x-direction.
A conductor carrying a currentI 14.3 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.124 N/m acts on the conductor in the negative y direction. (a) Determine the magnitude of the magnetic field in the region through which the current passes. (b) Determine the direction of the magnetic field in the region through which the current passes +x direction x direction ty direction -y direction +z...
The size of the magnetic force on a straight wire of length L carrying current I in a uniform magnetic field with strength B is F=ILBsin(?). Here ? is the angle between the direction of the current (along the wire) and the direction of the magnetic field. Hence Bsin(?) refers to the component of the magnetic field that is perpendicular to the wire, B?. Thus this equation can also be written as F=ILB?. The direction of the magnetic force on...
Problem-3 (20 points): The conductor, carrying current I to the right, has three segments: two straight segments and one semicircle as seen in the figure below. The magnetic field is uniform and points into the page. Calculate the total magnetic force on this conductor. X de X X F. dFR F X Op X X X EX sin e cos e de sin e de =-cos e dF = Idl x B dl = Rd0 F =Ilx B
. In the figure, two long and straight conductors are parallel to the z-axis and carry currents of 1 -20.0A and 1 15.0 A in opposite directions. Conductor 1 passes through (0, 0) while conductor 2 passes through 3.00 m, 0). (a) Find the location of the point where the net magnetic field due to the conductors is zero. (b) Suppose a third parallel conductor carrying a current of I,-10.0 A (same direction as Is) is placed where it passes...
Perfect conductor Pe= 4.5x10 C/m? 2.8 2 cm Perfect dielectric Perfect conductor Figure 2. Dielectric separated by two perfect conductors. A perfect dielectric is separated by two perfect-conductor plates as in Figure.2. On the surface of the top plate there is a uniform surface charge density of 4.5 x 10+ C/m2 as shown. In the perfect dielectric region the electric field is uniformly distributed. (25) a) Calculate the electric field intensity and discuss if there is a breakdown in the...
Find the direction of the magnetic force acting on a positive charge for this diagram, where y denotes the velocity of this positive charge and denotes the magnetic field. В What is the direction of the magnetic force on the positive charge in this diagram? The magnetic force points: A. to the right: B. out of the page: C. into the page D. to the left: E. upward: F downward; G. to the upper-left direction; H. to the upper right...