A 65.5 kg snowboarder heads down a 17.5° hill that has a height of 70.0 m....
A 65.5 kg snowboarder heads down a 17.5° hill that has a height of 70.0 m. If the hill is assumed to be frictionless and there is horizontal wind with a force of 25.3 N acting against the snowboarder, find the speed of the snowboarder as they reach the bottom of the hill using work and energy.
Homework Answers
Solution) m = 65.5 kg
Angle , theeta = 17.5°
h = 70 m
Horizontal wind force , F =25.3 N
V = ?
Net force , Fnet = F' - F
F' = mg(sin(theeta))
F' = 65.5×9.8×sin(17.5°)
F' = 193.02 N
Fnet = 193.02 - 25.3 = 167.72 N
Work energy theorem
W = KE
(Fnet)(L) = (1/2)(m)(V^2)
L = h/sin(theeta)
L = (70)/sin(17.5)
L = 232.78 m
(167.72)(232.78) = (1/2)(65.5)(V^2)
V^2 = 1192.11
V = (1192.11)^(1/2)
V = 34.5 m/s
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