Question

1. prompt a user to enter10 numbers.

2..If the user enters anything other than number 10, remind her that only numbers are required that let her retry.

3. Do not allow the user to enter more than 10 or less than 10.

4. Display the 10 numbers back to the user at the end.

5.Calculate the following statistics from the 10 numbers entered.

Minimum

maximum

mean

range

variance

standard deviation

Answer 1

There are few points unclear in the question like

1. in point no 3 does it say we can only enter a value between 1 to 10 (both inclusive) or any 10 values.

2. In point 1 it is not specified that should the numbers be integers or any real values.

3. The language to use is unspecified

So I made some assumptions like we can enter only 10 real value numbers [1 to 10] (both inclusive) and the values can be any real number between the range. And the programming language used is C++. (if you want C just follow the comment in the code).

// If want in c compile with gcc <filename.c> -lm
#include<bits/stdc++.h> // If want in C replace it with #include<stdio.h> and #include<math.h> //(both)
using namespace std; //If want in C remove this line
int n=10;

double find_min(double a[]){ // To find the minimum element of the sequence
int i=1;
double min1 = a[0];
for (i=1;i<n;i++){
if(a[i]<min1){
min1 = a[i];
}
}
return min1;
}

double find_max(double a[]){ // To find the maximum element of the sequence
int i=1;
double max1 = a[0];
for (i=1;i<n;i++){
if(a[i]>max1){
max1 = a[i];
}
}
return max1;
}

double find_mean(double a[]){ //To calculate mean of the sequence
double mean =0;
int i=0;
for(i=0;i<n;i++){
mean+=a[i];
}
return mean/n;
}

double find_variance(double a[],double mean){ // To calculate Variance using mean of sequence
double variance = 0;
int i=0;
for(i=0;i<n;i++){
variance += ((a[i]-mean)*(a[i]-mean));
}

return variance/n;
}

double find_standard_deviation(double variance){ // To calculate standard deviation using variance of the sequence

return sqrt(variance);
}

int main(){ // Driver function

double a[n];
int i=0;

for (i=0;i<n;i++){ // Take input 10 numbers until all are in range and feasible
printf("Enter an %dth number: ",i+1);
scanf("%lf",&a[i]);

if(a[i]>n || a[i]<1){ // Prompt when wrong input
printf("Entered number is not in range retry\n");
i--;
}
}

double min1 = find_min(a);
double max1 = find_max(a);
double mean = find_mean(a);
double var = find_variance(a,mean);
double sd = find_standard_deviation(var);

// Print all the parameters
printf("Minimum element is : %lf\nMaximum element is : %lf\n",min1,max1);
printf("Range is from %lf to %lf\n",min1,max1);
printf("Mean is %lf : \n",mean);
printf("Variance is : %lf \nStandard Deviation is : %lf\n",var,sd);

return 0;
}

Here is my sample output :

Hope this helps

If any problem ask in the comment section