Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor.
NO3- + 10e- -> N2 (E0 = +0.74 V)
H+ + 2e- -> H2 (E0 = -0.42 V)
If you balance and combine the reactions so that 220 molecules of H2 gas are oxidized to H+, how many molecules of NO3- will be reduced to dinitrogen gas?
Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons...
Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor. NO3- + 10e- -> N2 (E0 = +0.74 V) H+ + 2e- -> H2 (E0 = -0.42 V) If you balance and combine the reactions so that 155 molecules of H2 gas are oxidized to H+, how many molecules of NO3- will be reduced to dinitrogen gas?
1. What is the redox state of Oxygen in a molecule of diatomic hydrogen gas (H2)? 2. NO2- + 6e- -> NH4+ (-0.41 volts) & O2 + 4e- -> 2H2O (+0.82 volts) If you balance and combine the reactions so that 52 molecules of NH4+ are oxidized to NO2-, how many molecules of O2 will be reduced to H2O? 3. NO3- + 10e- -> N2 (E0 = +0.74 V) & H+ + 2e- -> H2 (E0 = -0.42 V) If...
Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. NO2- + 6e- -> NH4+ (-0.41 volts) O2 + 4e- -> 2H2O (+0.82 volts) If you balance and combine the reactions so that 82 molecules of NH4+ are oxidized to NO2-, how many molecules of O2 will be reduced to H2O?
Below are the paired reduction reactions for chemolithotrophic denitrification: these organisms are using nitrate as an electron accepter and are using hydrogen gas as a source of energy and electrons. 2NO3- + 10e- -> N2 (+0.74 volts) 2H+ + 2e- -> H2 (-0.42 volts) Using the information given, calculate the ΔE for this reaction, balance the full reaction to determine n, the number of electrons transfered when 97 molecules of H2 are oxidized. Finally, use the simplified Nernst Equation ΔG...
Below are the paired reduction reactions for chemolithotrophic denitrification: theseorganisms are using nitrate as an electron accepter and are using hydrogen gas as a source of energy and electrons. 2NO3- + 10e- -> N2 (+0.74 volts) 2H+ + 2e- -> H2 (-0.42 volts) Using the information given, calculate the ΔE for this reaction, balance the full reaction to determine n, the number of electrons transfered when 53 molecules of H2 are oxidized. Finally, use the simplified Nernst Equation ΔG =...
Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. NO2- + 6e- -> NH4+ (-0.41 volts) O2 + 4e- -> 2H2O (+0.82 volts) Using the information given, calculate the ΔE for this reaction, balance the full reaction to determine the n, the number of electrons transfered when 3 molecules of NH4+ are oxidized. Finally, use the simplified Nernst Equation ΔG = -nFΔE, where F...
Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon. CO2 + 8e- -> CH3COO-(-0.29 volts) SO42-+ 8e- -> H2S (-0.22 volts) If you balance and combine the reactions so that 41 molecules of CH3COO- are oxidized to CO2, how many molecules of H2S will be produced?
Using the table of reduction potentials (Eo) for the half-reactions shown, match the given redox reactions with their Eo and predict the change in free energy by stating whether the reactions will be exergonic or endergonic Exergonic 1.14 V 1.00 V 0.15 V 1.24 V 1.24 V Endergonic Reaction Free Energy Eo (Volts) CO2/glucose [-0.43] -0.5 -0.4 NAD /NADH 0.32 -0.3 NADH H 12 OH.ONAD 2HH2 -0.42] CO2/methanol [-0.38] Co2/acetate [-0.28] FADFADH2[-0.18] Pyruvatelactate [-0.19] 6CO, + 6H,O → 60, +...
Standard Reduction Please write your answers here Reduction Half-Reactin Potential (V) F2(g) + 2e-→ 2F-(aq) S2082 (ag) +2e-2SO42(ag) O2(g) + 4H(a)+ 4e 2H200) +2.87 +2.01 +1.23 +1.09 +0.80 +0.77 +0.54 +0.34 +0.15 +0.14 0.00 0.14 0.26 0.44 0.74 0.76 0.83 1.18 2.71 3.04 2 4 Ag+(aq) + e-→ Ag(s) Fe3+(ag)eFe2*(aq) 20)+ 2e- 21(aq) Cu2(ag)+ 2e Cus) SAMPLE QUIZ 4 S(s) + 2H+(aq) + 2e. → H2S(g) 2H(a)+ 2eH2g) Sn2(ag) 2e Sng) 1. What is the purpose of the salt bridge...
Standard Electrode Potentials at 25?C Reduction Half-Reaction E?(V) F2(g)+2e? ?2F?(aq) 2.87 Au3+(aq)+3e? ?Au(s) 1.50 Cl2(g)+2e? ?2Cl?(aq) 1.36 O2(g)+4H+(aq)+4e? ?2H2O(l) 1.23 Br2(l)+2e? ?2Br?(aq) 1.09 NO3?(aq)+4H+(aq)+3e? ?NO(g)+2H2O(l) 0.96 Ag+(aq)+e? ?Ag(s) 0.80 I2(s)+2e? ?2I?(aq) 0.54 Cu2+(aq)+2e? ?Cu(s) 0.16 2H+(aq)+2e? ?H2(g) 0 Cr3+(aq)+3e? ?Cr(s) -0.73 2H2O(l)+2e? ?H2(g)+2OH?(aq) -0.83 Mn2+(aq)+2e? ?Mn(s) -1.18 How can the table be used to predict whether or not a metal will dissolve in HCl? In HNO3? Drag the terms on the left to the appropriate blanks on the right to...