Question

Procedure 1:                                         &n

Procedure 1:                                           Run 1 Run 2

Mass of calorimeter and lid 117.1682 g    121.7315g

Mass of NaOH pellets 1.9985 g         1.9984g

Mass of calorimeter + lid + contents    217.0118 g    221.3835g

Initial Temperature                                 23.9 celsius 24.5 celsius

Final Temperature 27.1 celsius    28.0 celsius

Procedure 2:

Molarity of HCl solution = 2.10 M

Molarity of NaOH solution =2.00 M

Mass of calorimeter and lid                  126.3469g 126.3447g

Volume of HCl solution= 50.0 mL

Volume of NaOH solution= 50.0 mL

Mass of calorimeter +Lid + contents 226.1952g       229.3370g

Initial Temperature 23.5 celsius        24.0 celsius

Final Temperature 37.0 celsius       37.6 celsius

Procedure 3:

Molarity of HCl solution=1.10M

Mass of calorimeter and lid 123.1761g         123.5508g

Volume of HCl solution=100 mL

Mass of NaOH pellets 2.0079g               1.9944g

Mass of calorimeter+ lid+ contents 227.8055g 225.4040g

Initial Temperature                            24.1 celsius            23.9 celsius

Final Temperature 33.2 celsius           33.2 celsius

1. Calculate the moles of limiting reagent for each data run of each procedure. (Hint: For procedure 1, there is only one reagent, so this should be the limiting reagent. Remember that you can find the moles of a pure substance using the mass and the formula mass and your can find the moles of a solution using the molarity and the volume.)


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