Question

The following information is given for benzene at 1 atm:

Tb= 80.10°C Tm= 5.50°C

Specific heat gas = 1.040 J/g °C

Specific heat liquid = 1.740 J/g °C

Delta H Vap(80.10°C) = 393.3 J/g

Delta H Fusion (5.50°C) = 127.4J/g

A 38.30 g sample of liquid benzene is initially at 26.20°C. If the sample is heated at constant pressure ( = 1 atm), kJ of energy are needed to raise the temperature of the sample to 92.70°C.

Answer 1

This process have 3 steps:

1. Heating the liquid benzene until it reaches the boiling point (H₁).
2. Heating the liquid benzene at boiling point for the phase change (H₂).
3. Heating the gaseous benzene to final temperature (H₂).

Total amount of heat required for the whole process is given by:

----------------------------------------------------------

(Please rate the answer if you are satisfied. In case of any queries, please reach out to me via comments)