What is the molarity of a NaOH solution if 1.01 mL of the solution was required...
What is the molarity of a NaOH solution if 1.01 mL of the solution was required to reach the equivalence point with 0.00844 moles of KHP? Use the balanced equation between KHP and NaOH from the discussion in the lab.
Homework Answers
NaOH + KHP ----------------- NaKHP + H2O
1 mole 1 mole
number of moles of KHP = 0.00844 moles
according to the equation
1 mole of KHP = 1 mole of NaOH
0.00844 mole of KHP = 0.00844 moles of NaOH
number of moles of NaOH = 0.00844 moles
At equivalent point
the number of moles of NaOH is equal to the number of moles of KHP
so number of moles of NaOH = 0.00844 moles
Volume of the solution = 1.01 mL = 0.00101 L
Molarity = number of moles/volume in L = 0.00844/0.00101 = 8.356
Molarity of NaOH = 8.36M
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