Question

Determine the number of moles of C₂H₅OH in 147g of C₂H₅OH. Please show the conversion and unit work.

Answer 1

Ans :- 3.19 moles of C₂H₅OH

EXPLAINATION

First of all we have to know the molecular mass of C₂H₅OH (ethanol)

Molecular mass of ethanol = [(2*12.011)+(5*1.008)+(1*15.999)+(1*1.008)]

= 46.069 gram/moles

Because , atomic weight of C = 12.011 g/mol

atomic weight of H = 1.008 g/mol

atomic weight of O = 15.999 g/mol

Now, we have to calculate moles of ethanol in 147 g of ethanol

Moles of ethanol = given weight of ethanol/molecular weight of ethanol

= 147 g/46.069 g/mol

= 3.19 moles of C₂H₅OH (ethanol)