Question

entropy que seems too simple to be correct..

Using the standard entropy values:

SO2(g), So = +248.0 J mol–1 K–1
SO3(g), So = +256.0 J mol–1 K–1
NO(g), So = +210.6 J mol–1 K–1
NO2(g), So = +240.5 J mol–1 K–1

calculate the standard entropy change, ?So, for the reaction:
NO2(g) + SO2(g) ? NO(g) + SO3(g)
Enter your answer in J mol-1 K-1 to one decimal place. Do not enter units.

Thanks so much!

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Answer #1

NO2(g) + SO2(g) => NO(g) + SO3(g)

ΔSo(reaction) = So(products) - So(reactants)

= So(NO) + So(SO3) - So(NO2) - So(SO2)

= 210.6 + 256.0 - 240.5 - 248.0

= -21.9 J mol-1 K-1

answered by: eek
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