It requires 0.86 aJ to ionize a single gas phase Li atom. How much energy is required to ionize 6.022 × 10^23 gas phase Li atoms?
Energy for 1 atom = 0.86 aJ
= 0.86*10^-18 J
So,
for 6.022*10^23 atoms,
energy = 6.022*10^23 * 0.86*10^-18 J
= 5.18*10^5 J
Answer: 5.18*10^5 J
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