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A hydroelectric power plant has a turbine whose speed must be fixed at 240 rpm. The...

A hydroelectric power plant has a turbine whose speed must be fixed at 240 rpm. The turbine is impulse type with 12 m diameter. When the flow rate at the nozzle of the penstock is 10 m3/s, the generated electricity is 60 MW. Compute the velocity of the water jet (i.e., Find Vi).

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Answer #1

GIVEN DATA

Turbine Speed N = 240 rpm

Diameter = 12 m

Flow rate Q = 10 m^3/s

Power developed = 60 MW = 60 *10^6 W

Velocity of water jet (Vi) = ?

Ans :-  velocity of water jet = 116.44 m/s (please check attachments)

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