Question

Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin...

Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially at

x1 = 13.5 mm.

In this configuration, q1 exerts a repulsive force of 2.62 µN on q2. Particle q2 is then moved to

x2 = 17.8 mm.

What is the force (magnitude and direction) that q2 exerts on q1 at this new location? (Give the magnitude in µN.)

magnitude µNdirection ---Select--- +î −î +ĵ −ĵ +k̂ −k̂

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Answer #1

initial situation

F1 = k q1 q2 / r1^2

k q1 q2 = F1 r1^2

final situation

F2 = k q1 q2 / r2^2

F2 = F1 r1^2 / r2^2

F2 = 2.62* ( 13.5 / 17.8)^2

F2 = 1.507 uN

along +x axis

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Comment before rate in case any doubt, will reply for sure.. goodluck

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