For the following reactions, determine the species being oxidized or reduced, the balanced half reactions, and the balanced equation.
HCOOH+MnO4^- -> CO2+Mn^2+ in acidic solution
For the following reactions, determine the species being oxidized or reduced, the balanced half reactions, and...
For the following reactions, determine the species being oxidized or reduced, the balanced half reactions, and the balanced equation. Al(s)+Cu^2+(aq) -> Al^3+(aq)+CU(s)
1. Identify the species being oxidized and reduced in each of the following reactions, and determine the number of electrons (in mol) involved in the reaction: a. Crt + Sn4+ -> Cr3+ + Sn2+ b. 3 Hg2+ + 2 Fe (s) -> 3 Hg2+ 2 Fe3+ c. 2 As (s) + 3 Cl2 (8) 2 AsCl3
Balance the following redox half-cell reactions. Write your final equations with the oxidized species on the left hand side of the equation, and the reduced species on the right hand side of the equation. Don’t forget to pay careful attention to the stoichiometry of the various species. a) Mn2O3/MnO4- b) H2S/HSO4- c) CrO42-/Cr2O3 d) Eu2+/EuO2-
Please show all work. Thank you. 1 Write the balanced half reactions of the following reactions: a. NiO2 + 2 H2O + Fe -Ni (OH)2 + Fe(OH)2 in basic solution b. CO2 + 2 NH,OH →CO + N2 + 3H2O in basic solution WRC c. 2 H+ + H,02 + 2 Fe2+ + Fe3+ + 2 H2O in acidic solution CE d. H+ + 2 H2O + 2 MnO4 + 5 SO2 → Mn* + 5 HSO4 in acidic solution
For each of the following redox reactions, determine which element is being reduced and which is being oxidized. (help it should be a one element answer!!) (a) MnO2(aq) + K2C2O4(aq) + 2 H2SO4(aq) → MnSO4(aq) + K2SO4(aq) + 2 CO2(g) + 2 H2O(l) element being reduced : Mn Correct: Your answer is correct. element being oxidized: ?? (c) 2 CrO3(aq) + 3 CH3CH2OH(aq) → Cr2O3(aq) + 3 CH3CHO(aq) + 3 H2O(l) element being reduced ?? element being oxidized ??
Part B: Basic Conditions Using the half-reaction method, balance the following redox reactions under basic conditions and identify which of the reactants is being reduced and which is being oxidized. 7. SO32- + Cu(OH)2 → S022- + Cu(OH) a. Oxidized: b. Reduced: c. Balanced Equation: 8. O2 + Mn(OH)2 → MnO2 a. Oxidized: b. Reduced: c. Balanced Equation: 9. NO;' + H2 → NO a. Oxidized: b. Reduced: c. Balanced Equation:
How do I solve the following redox reactions? What are the balanced half-reactions? What is the final balanced equation? Problems 1. MnO4 (aq) + SO32- (aq) → MnO2 (s) + SO42- (aq) in basic solution 2. NO2" (aq) + Al(s) NH3(aq) + Al(OH)4 (aq) in basic solution 3. Mn2+ (aq) + NaBiO3 (s) → Bi* (aq) + MnO4 (aq) + Nat (aq) in acidic solution 4. As2O3 (s) + NO3- (aq) → H3ASO4 (aq) + N2O3 (aq) in acidic solution...
5) Determine which element is oxidized and which element is reduced in the following redox reactions. (4) Fe2O3 + CO ® Fe + CO2 Element oxidized ____________________ Element reduced _________________ Cr2O72- + H2C2O4 ® Cr3+ + CO2 Element oxidized ____________________ Element reduced ___________________ 6) Determine the balanced molecular, ionic and net ionic equations for the following single displacement (replacement) reaction. (9) (ME) Al(s) + HCl(aq) ® (IE) (NIE)
For each of the following redox reactions (not balanced), define which component is being reduced and which is being oxidized as the reaction progresses. *It may be quite beneficial to draw the element in question and its electrons in its reactant and product state. 1) C6H12O6 + O2 → CO2 + H2O Carbon is Oxygen is 2) CO2 + H2O + CHA + O2 Carbon is Oxygen is 3) NAD + H+ + 2e + Malate → NADH + Oxaloacetate...
Consider the following reactions and determine which specie will be oxidized and which one will be reduced, also, determine the reducing agent, the oxidizing agent, which specie will be found at the anode and which one will be found at the cathode. How many moles of electrons are transferred and how many Faradays of energy will be required? 1. MnO, + NO, Mn + NO, Species oxidized Reduced Reducing Found at the Oxidizing Agent Agent Found at the anode cathode...