Question

The recipe for approximately 100 mL of carbolfuchsin primary stain is listed below. Reagent Amount Basic fuchsin 0.3 g Ethanol 10.0 mL DI H2O 95.0 mL Phenol 5.0 mL If you wanted to make approximately 50 mL of solution by suspending the reagents in 47.5 mL of water, how many grams of basic fuchsin would be required? Report your answer to two decimal places.

Answer 1

Basic fuchsin (C1) = 0.3 g

Ethanol = 10.0 mL

DI H2O = 95.0 mL

Phenol = 5.0 mL

Total volume = 110ml

Volume needed = 50ml

If 0.3gm is added to 110ml

Amount of basic fuchsin needed = (0.3x50)/110 = 0.15gm