Two 2.2 cm -diameter disks face each other, 1.9 mm apart. They are charged to ±20nC.
A.
What is the electric field strength between the disks?
B.
A proton is shot from the negative disk toward the positive disk. What launch speed must the proton have to just barely reach the positive disk?
Thanks
(a) E = Q / oA
where A is area of disk = pi * r2
where , r = 2.2 / 2 = 1.1 cm
E = 20e-9 / 8.85e-12 * pi * 0.0112
E = 5.945e6 N/C
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(b) using Newton's second law
F = ma
qE = ma
a = qE / m
a = 1.6e-19 * 5.945e6 / 1.67e-27
a = 5.695e14 m/s2
now, using kinematics
v2 - u2 = 2ad
as proton comes to stop at positive plate v = 0
u = sqrt (2ad)
u = sqrt ( 2 * 5.695e14 * 1.9e-3)
u = 1.47e6 m/s
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