Question

To what volume should you dilute 132 mL of an 8.05 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.45 g CuCl2? Express your answer in milliliters.

Answer 1

first calculate final molarity of the solution

molarity = ( W/MW) (1000 / V in mL)

Molarity = (4.45 / 134.45) (1000 / 49)

molarity = 0.675 M

now according to dilution law

M1V1 = M2V2

M1 = 8.05 M , V1 = 132 mL

M2 = 0.675 M , V2 = ?

V2 = (M1V1 /M2)

V2 = (8.05 x 132 / 0.675)

V2 = 1574 mL

answer = 1574 mL