Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+2Z2⟶2XZ2Δ?2=−190 kJ 2Y2+Z2⟶2Y2ZΔ?3=−220 kJ Calculate the change in enthalpy for...

Question

Question

Given the thermochemical equations

X2+3Y2⟶2XY3Δ?1=−340 kJ

X2+2Z2⟶2XZ2Δ?2=−190 kJ

2Y2+Z2⟶2Y2ZΔ?3=−220 kJ

Calculate the change in enthalpy for the reaction

4XY3+7Z2⟶6Y2Z+4XZ2

Answer 1

Answer #1

Answer 2

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