Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−310 kJX2+3Y2⟶2XY3ΔH1=−310 kJ X2+2Z2⟶2XZ2ΔH2=−110 kJX2+2Z2⟶2XZ2ΔH2=−110 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change...

Question

Question

Given the thermochemical equations

X2+3Y2⟶2XY3ΔH1=−310 kJX2+3Y2⟶2XY3ΔH1=−310 kJ

X2+2Z2⟶2XZ2ΔH2=−110 kJX2+2Z2⟶2XZ2ΔH2=−110 kJ

2Y2+Z2⟶2Y2ZΔH3=−270 kJ2Y2+Z2⟶2Y2ZΔH3=−270 kJ

Calculate the change in enthalpy for the reaction. (in kj)

4XY3+7Z2⟶6Y2Z+4XZ2

Answer 1

Answer #1

X2 +3Y→ 2XY, AH, = -310 kJ ---> (1) X2 +222 +2xZ, AH2 =-110 kJ ---> (2) 2Y2 +Z2 +2Y Z AH=-270 kJ ---> (3) Let us take the rev

Answer 2

Similar Homework Help Questions

Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−380 kJ ' X2+2Z2⟶2XZ2ΔH2=−180 kJ 2Y2+Z2⟶2Y2ZΔH3=−250 kJ Calculate the change in enthalpy...

Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−380 kJ ' X2+2Z2⟶2XZ2ΔH2=−180 kJ 2Y2+Z2⟶2Y2ZΔH3=−250 kJ Calculate the change in enthalpy for the reaction. 4XY3+7Z2⟶6Y2Z+4XZ2
Given the thermochemical equations X2+3Y2⟶2XY3 ΔH1=−320 kJ X2+2Z2⟶2XZ2 ΔH2=−170 kJ 2Y2+Z2⟶2Y2Z ΔH3=−290 kJ Calculate the change...

Given the thermochemical equations X2+3Y2⟶2XY3 ΔH1=−320 kJ X2+2Z2⟶2XZ2 ΔH2=−170 kJ 2Y2+Z2⟶2Y2Z ΔH3=−290 kJ Calculate the change in enthalpy for the reaction. 4XY3+7Z2⟶6Y2Z+4XZ2
Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+2Z2⟶2XZ2Δ?2=−190 kJ 2Y2+Z2⟶2Y2ZΔ?3=−220 kJ Calculate the change in enthalpy for...

Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+2Z2⟶2XZ2Δ?2=−190 kJ 2Y2+Z2⟶2Y2ZΔ?3=−220 kJ Calculate the change in enthalpy for the reaction 4XY3+7Z2⟶6Y2Z+4XZ2

Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+2Z2⟶2XZ2Δ?2=−120 kJ 2Y2+Z2⟶2Y2ZΔ?3=−260 kJ Calculate the change in enthalpy for...

Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+2Z2⟶2XZ2Δ?2=−120 kJ 2Y2+Z2⟶2Y2ZΔ?3=−260 kJ Calculate the change in enthalpy for the reaction. 4XY3+7Z2⟶6Y2Z+4XZ2 Δ?=__________kJ
CHEMISTRY...Given the following thermochemical equations: Given the following thermochemical equations AHI -360 kJ 2 XL AP,...

CHEMISTRY...Given the following thermochemical equations: Given the following thermochemical equations AHI -360 kJ 2 XL AP, 110 kJ AH, 280 kJ 2Y. Calculate the change in enthalpy for the following reaction: AH Number kJ
Calculate the change in enthalpy for the following reaction: Given the following thermochemical equations: AH,370 kJ...

Calculate the change in enthalpy for the following reaction: Given the following thermochemical equations: AH,370 kJ ΔΗ,--180 kJ AH,230 kJ Calculate the change in enthalpy for the following reaction: Number kJ

Given the thermochemical equations X, +3Y, 2XY, AH = -320 kJ X+2Z 2XZ AH = -160...

Given the thermochemical equations X, +3Y, 2XY, AH = -320 kJ X+2Z 2XZ AH = -160 kj 2 Y2 + Z2 2Y, Z AH, = -270 kJ Calculate the change in enthalpy for the reaction. 4XY, +72, 6Y Z + 4 XZ, AH = KJ
Given the following thermochemical equations: LM'=-380 kJ H,--180 kJ AH,--240 kJ Calculate the change in enthalpy...

Given the following thermochemical equations: LM'=-380 kJ H,--180 kJ AH,--240 kJ Calculate the change in enthalpy for the following reaction: xy,.nz, →evp.ar, a v-Ele. Jul Number k.J
ment Score: 767/2000 Resources Hint Che Question 15 of 20 > Given the thermochemical equations X,...

ment Score: 767/2000 Resources Hint Che Question 15 of 20 > Given the thermochemical equations X, +3Y, — 2XY; AH = -310 kJ X, +2Z) — 2XZ, AH) = -130 kJ 2Y, +Z, — 28,Z AH; = -220 kJ Calculate the change in enthalpy for the reaction. 4 XY, +72, — 6Y,Z+4 XZ, AH = v U 1 0

Given the thermochemical equations X 2 + 3 Y 2⟶ 2 XY3 Δ H 1 =...

Given the thermochemical equations X 2 + 3 Y 2⟶ 2 XY3 Δ H 1 = − 330 kJ X 2 + 2 Z2 ⟶ 2 XZ2 Δ H 2 = − 130 kJ 2 Y2 + Z2 ⟶ 2 Y2 Z Δ H 3 = − 250 kJ Calculate the change in enthalpy for the reaction. 4 XY3 + 7 Z2 ⟶ 6 Y2 Z + 4 XZ2 Δ H = kJ