A sample of carbon dioxide gas has a pressure of 1.89 atm and a volume of 21.5 mL at a temperature of 76.2 ℃. How many molecules of carbon dioxide gas are in the sample?
a) 0.0142
b) 8.54 × 1020
c) 8.54 × 1023
d) 70.7
e) 4.26 × 1025
To calculate the number of molecules of carbon dioxide gas in the sample, we can use the ideal gas law equation:
where: P = Pressure of the gas (in atm) V = Volume of the gas (in liters) n = Number of moles of the gas R = Ideal gas constant (0.0821 L.atm/mol.K) T = Temperature of the gas (in Kelvin)
First, we need to convert the given values to the appropriate units:
Pressure (P) = 1.89 atm Volume (V) = 21.5 mL = 0.0215 L Temperature (T) = 76.2 ℃ = 76.2 + 273.15 = 349.35 K (converted to Kelvin)
Now, let's calculate the number of moles (n):
The number of molecules can be calculated using Avogadro's constant, which is approximately molecules/mol.
Number of molecules =
Number of molecules ≈ molecules
So, the correct answer is option (b) molecules.
To find the number of molecules of carbon dioxide gas in the sample, we can use the ideal gas equation:
PV = nRT
where: P = pressure (in atm) V = volume (in L) n = number of moles R = ideal gas constant (0.08206 L atm / (mol K)) T = temperature (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin: T(K) = 76.2 ℃ + 273.15 = 349.35 K
Next, we can rearrange the ideal gas equation to solve for the number of moles (n):
n = PV / RT
Now, let's plug in the given values:
P = 1.89 atm V = 21.5 mL = 21.5 / 1000 L (convert from mL to L) R = 0.08206 L atm / (mol K) T = 349.35 K
n = (1.89 atm * 21.5 / 1000 L) / (0.08206 L atm / (mol K) * 349.35 K)
n ≈ 0.0142 mol
Finally, to find the number of molecules (N), we can use Avogadro's number:
N = n * NA
where NA is Avogadro's number (6.022 x 10^23 mol^-1).
N ≈ 0.0142 mol * (6.022 x 10^23 mol^-1)
N ≈ 8.54 x 10^21
So, the correct answer is b) 8.54 x 10^20 molecules of carbon dioxide gas in the sample.
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