(1 point) Consider a proton in a magnetic field 6.5 T (may be part of an...
(1 point) Consider a proton in a magnetic field 6.5 T (may be part of an atom and or molecule). The dipole moment of a proton is 1.41e−26 J/T. The magnetic moment changes orientation from parallel to anti-parallel. Give the change in energy in μeV. ΔU = μeV Frequency can also be used as a unit for energy using the conversion factor 4.14 μeV = 1000 MHz. Using this conversion give the energy in MHz. f = MHz The relationship between the magnetic moment of the proton and its angular momentum is more complicated than for the electron since the proton has internal quark structure. μp=2.79eℏ/mp.
Homework Answers
given, 4.14 
eV = 1000
MHZ
so, 1 eV = 1000/4.14
MHZ
so 
U = 1.145 x
1000/4.14 MHZ = 276.57 MHZ.
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