Question

Skills Needed: cin, cout, constants, arithmetic expressions, rounding, int main, meaningful variable names, spacing, indentation, documentation, output.

Computing Basic Geometric Formulas

Write a program to compute answers to some basic geometry formulas. The program prompts the user to input a length (in centimeters) specified as a floating point value. The program then echoes the input and computes areas of squares and circles and the volume of a cube. For the squares, you will assume that the input length value is the length of a side. For the circles, this same value becomes the diameter. Use the meter value input to calculate the results in square (or cubic) meters and then print the answers in square (or cubic) meters.

Area of a square (length times width)

Area of a circle (pi times radius squared)

How much bigger the area of the square is than the circle (see previous calculations)

Round the length down to the next whole number of meters, compute the volume of a cube with this value as the length of its side

Round the length up to the next whole number of meters, compute the volume of a cube with this value as the length of its side.

You are to run the program three times using the following input values:

1000

1999.9

299.4

Please turn in the program and the outputs of running the program three times as directed. Be sure to use good style, appropriate comments and make use of constants in this program.

Important Notes

For the constant PI, please use 3.14159

Use the floor() and ceil() functions to round down and up respectively. For example, ceil(3.02) is 4.

Be sure to #include to get access to these two functions

Sample Output

Your output format should look similar in style to the one below.

Geometry formulas by (Your name)

Enter one floating point number for length, 123.4

The number you entered is 123.4 cm or 12.34xx m.

Area of square xx.xxxxxxx sq. m.

Area of a circle xx.xxxxxxx sq. m.

Difference is xx.xxxxxxxx sq. m.

Cube volume rounded down is xx.xxxxxxxx cu. m.

Cube volume rounded up is xx.xxxxxxxx cu. m.

Press any key to continue

Answer 1

#include <iostream>

#include <iomanip>

#include <cmath>

#define PI 3.14159

using namespace std;

int main()

{

double lenInCm, lenInMeter;

cout << endl << "GEOMETRY FORMULAS BY (YOUR NAME)" << endl;

cout << endl << "Enter one floating point number for length: ";

cin >> lenInCm;

lenInMeter = (lenInCm / (double)100);

cout << "The number you entered is " << lenInCm << " cm or " << setprecision(4) << fixed << lenInMeter << " m." << endl;

double areaSquare = (pow(lenInMeter, 2));

cout << "Area of square " << setprecision(7) << fixed << areaSquare << " sq. m." << endl;

double radius = (lenInMeter / 2);

double areaCircle = (PI * pow(radius, 2));

cout << "Area of circle " << setprecision(7) << fixed << areaCircle << " sq. m." << endl;

double diff = (areaSquare - areaCircle);

cout << "Difference is " << setprecision(8) << fixed << diff << " sq. m." << endl;

double lenRoundDown = floor(lenInMeter);

double cubeVolumeDown = pow(lenRoundDown, 3);

cout << "Cube volume rounded down is " << setprecision(8) << fixed << cubeVolumeDown << " cu. m." << endl;

double lenRoundUp = ceil(lenInMeter);

double cubeVolumeUp = pow(lenRoundUp, 3);

cout << "Cube volume rounded up is " << setprecision(8) << fixed << cubeVolumeUp << " cu. m." << endl;

}

***************************************************************** SCREENSHOT **********************************************************

OUTPUT 1 (Input: 1000):

OUTPUT 2 (Input: 1999.9):

OUTPUT 3 (Input: 299.4):