Question

Calculates the dimensions for various fish pond configurations. Specifically, the program will calculate the volume for the pond in cubic feet, the surface area of the sides and bottom of the fish pond, and the area of a 2-foot wide border around the edge of the pond.
Ponds come in predefined sizes and shapes.
     There are:
    - circular ponds, diameter: 5 feet

    - square ponds, side: 5 feet

     - rectangular ponds, dimensions: 4 feet by 7 feet

     - ovoid ponds, dimensions: 4 feet by 6 feet
The "oval" can be decomposed into two semicircles attached to a rectangle.

     - "L"-shaped ponds: overall dimensions: 6 feet by 10 feet
The "L" can be decomposed into three smaller rectangles; alternately, it could be viewed as a large rectangle with a corner excised.

The basic depth of a pond is 24 inches. For the Challenge option, depth is variable:    18, 24, or 30 inches deep. Remember that 12 inches is one foot, so these values translate into 1.5, 2.0, or 2.5 feet deep, respectively.

There are two enhancements for the Standard version over the Minimal version:

• The program will perform the calculations within the script file.

• Reported the area of a two-foot wide border around the pond.

The program will still assume that the user input is accurate. If unexpected values are entered, the behavior of the script is "undefined".

Program-Internal Calculations

For the Minimal version, you could calculate the values for the volume and surface area external to the Python script and just print out the numbers. For the Standard and Challenge versions,all of the calculations must be present within the Python script.

• The script shall calculate the values based on the dimensions given above and the user's input. That is, the script needs to calculate the volume and area, rather than just output precalculated values.

• The script shall use math.pi for the value of π, rather than some other approximation.
  Note: To use the value math.pi, your script file will need to include the following declaration toward the top of the script, after the header comment: import math

The values can be used for the shapes are the ones that appear on the schematic diagrams of the shapes. They are repeated in the table below.

Shape	Given Values
circle	5
square	5
rectangle	4, 7
oval	4, 6
L	3, 6, 5, 10

Let's see how this would work. As an example, here are the calculations for a circular pond of the standard depth, 24 inches.

The base of the pond is a circle, 5 feet in diameter. So, the radius is 5/2 or 2.5 feet.
The area of the base is the area of the circle, π ·r².
The perimeter of the base is the circumference of the circle, 2π ·r.
The depth is 24 inches, or 2 feet.
So, the volume is the area of the base times the depth.
The surface area is the area of the base plus the area of the sides.
The area of the sides is the depth times the perimeter of the base.

Converting this into Python is pretty straight forward:

r = 5 / 2
base_area = math.pi * r ** 2
base_perim = 2 * math.pi * r
depth = 2.0
side_area = depth * base_perim
volume = base_area * depth
surface_area = base_area + side_area

Note: we get the 5 because the user selectedcircle. That selection also gives us the formulae for area and perimeter of the base. The depth is derived from the input depth value of 24 inches. This could be either calculated or just use the correspondences in the following table.

Inches	Feet
18	1.5
24	2.0
30	2.5

Border

For the Standard version, the program shall calculate the area of a two-foot wide border around the pond. This calculation should also occur within the Python script. The mathematics of calculating the area of the path is left as an exercise for the student. They can be calculated using simple plane geometric figures.
Hint: It's probably easiest to calculate the border by subtracting the top of the pond from a larger solid.

Sample runs, Standard version

The user input is shown in blue bold text.

Fish ponds are available in the following shapes:
circle, square, rectangle, oval, L
Please select the shape for your fish pond:square

The volume of your fish pond is 50.000 cubic feet.
The surface area of your fish pond is 65.000 square feet.
The area of the border is 56.000 square feet.

The user input is shown in blue bold text.

Fish ponds are available in the following shapes:
circle, square, rectangle, oval, L
Please select the shape for your fish pond:circle

The volume of your fish pond is 39.270 cubic feet.
The surface area of your fish pond is 51.051 square feet.
The area of the border is 43.982 square feet.

The expected values for the volume and surface area are given in the Minimal portion of this write-up. If the calculated values do not agree with the values listed above, the functionality score will not be greater than the minimal score. (It could be less if the values are not reported with three places after the decimal point.)

Answer 1

# cook your dish here
print ("Available Fish Ponds are in the following shapes: circle, square, rectangle, oval, L")
print ("Select the shape for your fish pond: ",end=" ")
Pondshape = input()
print ("Depth of fish pond for challenge option : 18, 24, 30",end=" ")

Pdepth = float(input())
if (Pondshape == "circle"):
print ("Volume of your fish pond is %.3f" % (3.14159*2.5*2.5*(Pdepth/12))+(" cubic feet."))
print ("Surface area of your fish pond is %.3f" % (3.14159*2.5*2.5 + (2*3.14159*2.5*(Pdepth/12))) + " square feet.")

elif (Pondshape == "square"):
print ("Volume of your fish pond is %.3f" % (5*5*(Pdepth/12))+(" cubic feet."))
print ("Surface area of your fish pond is %.3f" % (25 + (4*5*(Pdepth/12))) + " square feet.")

elif (Pondshape == "rectangle"):
print ("Volume of your fish pond is %.3f" % (7*4*(d/12))+(" cubic feet."))
print ("Surface area of your fish pond is %.3f" % (28 + (22*(Pdepthd/12))) + " square feet.")

elif (Pondshape == "oval"):
print ("Volume of your fish pond is %.3f" % ((2*4 + 3.14159*2*2)*(Pdepth/12))+(" cubic feet."))
print ("Surface area of your fish pond is %.3f" % ((2*4 + 3.14159*2*2) + (2*3.14159*2*(Pdepth/12)) + (4*(Pdepth/12))) + " square feet.")

else:
print ("Volume of your fish pond is %.3f" % ((10*3 + 5*3)*(Pdepth/12))+(" cubic feet."))
print ("Surface area of your fish pond is %.3f" % ((10*3 + 5*3) + 20*(Pdepth/12) + 12*(Pdepth/12)) + " square feet.")