Question

PYTHON

Stuck on this problem:

Write a program for playing a game with the computer. First, generate a random integer in the range of 6 through 9. This will be the computer’s pick. Then generate three random integers for the human player. These random integers are in the range of 1 through 10. If any of these three random integers is greater than the computer’s pick, the human player wins the game. Otherwise, the human player loses. You must use a for loop to generate these three random integers. In each iteration, generate and display one random integer. If it is larger than the computer’s pick, display “You have won the game” and break out of the loop. If the human player cannot get a random integer larger than computer’s pick after three iterations , display “sorry you have lost the game”. The following is an example: Computer's pick: 9 Your pick: 8 Your pick: 3 Your pick: 2 Sorry, you have lost the game Another example: Computer's pick: 6 Your pick: 5 Your pick: 8 You have won the game ***Cannot use "flag" because we have not covered this yet in class.

Answer 1

#To generate random numbers we need to import random class
import random as r
computer=r.randint(6,9)#Generating random for computer.

print("Computer's Pick : ",computer)#printing the Computer's Pick.

#for loop to generate the random numbers for human user.
for i in range(3):

human=r.randint(1,10)#random number generating for human

print("Human's pick "+str(i)+":",human)#printing Human's Pick

if(human > computer):#condition to check whether human's pick is greater than Computer's Pick
print("You have won the game")
break #breaks only if humans pick is greater than computer's pick.

#if the loop is not broke that means all the human's picks are lesser than computer's pick

#if the loop breaks then the recent human value is greater than Computer's pick.

if(human <= computer):
print("sorry you have lost the game")

OUTPUT:-