Question

Using C Write the function:

long sum (long *a, long n);

This function takes an array a and an integer n, and returns the sum of the n first long integers in a. You are not allowed to use the notation a[i], you must use pointer arithmetic.

Answer 1

#include <stdio.h>
#include<stdlib.h>
long sum(long *a,long n)
{
long res=0;
for(int i=0;i<n;i++)
res=res + *(a+i);   // *(a+i) is same as a[i]
return res;
}
int main()
{
long n;
printf("Enter the value of n ---->");
scanf("%ld",&n);
long *a=(long*)malloc(n*sizeof(long)); //Dynamic allocation of array using malloc
printf("Enter the array element ---->");
for(int i=0;i<n;i++)
{
long temp;
scanf("%ld",&temp);
*(a+i)=temp; // *(a+i) is same as a[i]
}
long sum_result=sum(a,n);
printf("The sum of the array of n element is ------> %ld",sum_result);
return 0;
}