A 9 g lead bullet leaves the rifle at a temperature of 110°C and hits a...
A 9 g lead bullet leaves the rifle at a temperature of 110°C and hits a steel plate. If the bullet melts on impact, what is the minimum speed it must have?
Homework Answers
given
m = 9 g = 9*10^-3 kg
we know, specific heat of lead, C = 128 J/(kg C)
latent of melting of lead, L = 23*10^3 J/kg
we know, melting point of leat, T = 327.5 C
heat required to melt the lead bullet, Q = m*C*(327.5 - 110) + m*L
= 9*10^-3*128*(327.5 - 110) + 9*10^-3*23*10^3
= 457.6 J
so, reuired kinetic energy of the bullet, KE = 457.6 J
use, (1/2)*m*v^2 = KE
==> v = sqrt(2*KE/m)
= sqrt(2*457.6/(9*10^-3))
= 319 m/s <<<<<<<<<<<<<<<---------------------Answer
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