Use the normal distribution of fish lengths for which the mean is 9 inches and the standard deviation is 4 inches. Assume the variable x is normally distributed.
What percentage of the fish are longer than 13 inches?
Solution :
Given ,
mean = = 9
standard deviation = = 4
P(x >13 ) = 1 - P(x< 13)
= 1 - P[(x -) / < (13-9) / 4]
= 1 - P(z <1 )
Using z table
= 1 - 0.5
= 0.5
answer=50%
Use the normal distribution of fish lengths for which the mean is 9 inches and the...
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