For a standard normal probability distribution, find the following
a) P(z<1.2)
b) P(z<−0.45)
c)P(−0.4<z<1.8)
Solution :
Given that,
Using standard normal table ,
a)
P(z < 1.2) = 0.8849
b)
P(z < -0.45) = 0.3264
c)
P(-0.4 < z < 1.8)
= P(z < 1.8) - P(z < -0.4)
= 0.9641 - 0.3446
= 0.6195
P(-0.4 < z < 1.8) = 0.6195
For a standard normal probability distribution, find the following a) P(z<1.2) b) P(z<−0.45) c)P(−0.4<z<1.8)
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