A 65.0-kg skier is skiing down a 35.0o slope. If the friction force on her ski...

Question

Question

A 65.0-kg skier is skiing down a 35.0^o slope. If the friction force on her ski is 32.0N, what is her acceleration down the slope?

Answer: m/s²

What is the normal force on the skier?

Answer 1

Answer #1

force acting down the plane = mg sin

= 65*9.8*sin 35 = 365.4 N

net force acting along the plane = (365.4 - 32)= 333.4 N

acceleration = net force / mass

= 333.4 / 65 = 5.13 m/s^2

Normal force = mg cos

= 65*9.8*cos 35 = 521.8 N

Answer 2

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