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a 75.0 skier is descending a ski run in marmot basin with a 22.5 degrees slope...

a 75.0 skier is descending a ski run in marmot basin with a 22.5 degrees slope (from the horizontal). If the force of friction acting against her as she skies is 50 N, what will be the her acceleration down the slope? draw a free-body diagram
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Answer #1

mg sing ing cos θ mg

Wt-Ff=ma --> a~3.1 m/s2

Wt=mgsin(theta)~281.3 N

theta=22.5 deg

Ff=50 N

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