In 2003, an organization surveyed 1 comma 500 adult Americans and asked about a certain war,...
In 2003, an organization surveyed 1 comma 500 adult Americans and asked about a certain war, "Do you believe the United States made the right or wrong decision to use military force?" Of the 1 comma 500 adult Americans surveyed, 1 comma 090 stated the United States made the right decision. In 2008, the organization asked the same question of 1 comma 500 adult Americans and found that 570 believed the United States made the right decision. Construct and interpret a 90% confidence interval for the difference between the two population proportions, p 2003 minus p 2008.
A. The lower bound of a 90% confidence interval is...
B. The upper bound of a 90% confidence interval is...
Homework Answers
Here, , n1 = 1500 , n2 = 1500
p1cap = 0.7267 , p2cap = 0.38
Standard Error, sigma(p1cap - p2cap),
SE = sqrt(p1cap * (1-p1cap)/n1 + p2cap * (1-p2cap)/n2)
SE = sqrt(0.7267 * (1-0.7267)/1500 + 0.38*(1-0.38)/1500)
SE = 0.017
For 0.9 CI, z-value = 1.64
Confidence Interval,
CI = (p1cap - p2cap - z*SE, p1cap - p2cap + z*SE)
CI = (0.7267 - 0.38 - 1.64*0.017, 0.7267 - 0.38 + 1.64*0.017)
CI = (0.3188 , 0.3746)
Lower bound = 0.3188
Upper bound = 0.3746
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In 2003, an organization surveyed 1 comma 500 adult Americans
and asked about a certain war,...
In 2003, an organization surveyed 1,500 adult Americans and asked about a certain war, "Do you...
In 2003, an organization surveyed 1,500 adult Americans and
asked about a certain war, "Do you believe the United States made
the right or wrong decision to use military force?" Of the 1,500
adult Americans surveyed, 1,080 stated the United States made the
right decision. In 2008, the organization asked the same question
of 1,500 adult Americans and found that 575 believed the United
States made the right decision. Construct and interpret a 90%
confidence interval for the difference between...
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