Assume the random variable X is normally distributed, with mean
muμequals=5050
and standard deviation
sigmaσequals=55.
Find the
12 th12th
percentile.
Given that,
mean = = 50
standard deviation = = 5
Using standard normal table,
P(Z < z) = 12%
= P(Z < z) = 0.12
z = -1.18 Using standard normal z table,
Using z-score formula
x= z * +
x= -1.18 *5+50
x= 44.1
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