Consider a router that interconnects three subnets: Subnet 1, Subnet 2, and Subnet 3. Suppose all of the interfaces in each of these three subnets are required to have the prefix 223.1.17/24. Also suppose that Subnet 1 is required to support up to 62 interfaces, Subnet 2 is to support up to 106 interfaces, and Subnet 3 is to support up to 15 interfaces. Provide three network addresses (of the form a.b.c.d/x) that satisfy these constraints.
Solution
There are lots of possibilities are there
Subnet 1 is required to support 62 interface
62 can be rounded to nearest 2 power that is
2 6 = 6 bits
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Subnet 2 is required to support 106 interfaces
106 addresses can be round up to 128 in the 2 power
2 7 = 128
so we need 7 bits
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Subnet 3 is required to support 15 interfaces
15 addresses can be round up to 16 in the 2 power
2 4 = 16
so we need 4 bits
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Subnet
1
223.1.17.128/26
Subnet
2
223.1.17.0/25
Subnet
3
223.1.17.192/28
Please note that other possibilities also there for the question
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