Show the solution and determine the best answer
A short transmission line supplies power to a load of 30 MVA at
230 kV, 0.8 lagging power factor. Calculate the percent regulation
for a line impedance of (12+j36) ohms.
a. 1.78%
b. 1.87%
c. 2.18%
d. 2.52%
The shunt capacitive reactance of a 40km 34.5 kv line is 90 Kohms
per km. What is the total capacitive reactance of the line,
a. 3.5 M ohms
b. 2.25 Kohms
c. 6.75 Kohms
d. 3.6 Mohms
1) %regulation for short transmission line =
Power factor ,
Z=R +jX = 12+j36 ohms
Vr=230KV
By substituting. All value in the given formula. We get
Therefore percentage regulation is 1.76% which is near to option a so a is correct option .
2) given shunt capacitive reactance is 90k ohms per km
For 40km the reactance is 90k*40= 3600kohms =3.6 Mohms so option d is correct option .
Show the solution and determine the best answer A short transmission line supplies power to a...
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