According to a certain country's department of education, 39.7% of 3-year-olds are enrolled in day care....
According to a certain country's department of education,
39.7%
of 3-year-olds are enrolled in day care. What is the probability that a randomly selected 3-year-old is enrolled in day care?
The probability that a randomly selected 3-year-old is enrolled in day care is
nothing .
(Type an integer or a decimal.)
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According to a certain country's department of education,
39.7%
of 3-year-olds are enrolled in day care....
A country's education department reported that in2015,66.8% of students enrolled in college or a trade school...
A country's education department reported that in2015,66.8% of students enrolled in college or a trade school within 12months of graduating high school. In 2017, a random sample of171individuals who graduated from high school12months prior was selected. From this sample,108 students were found to be enrolled in college or a trade school. a. Construct a90%confidence interval to estimate the actual proportion of students enrolled in college or a trade school within 12months of graduating from high school in 2017.
Heights of 10 year olds. Heights of 10 year olds, regardless of gender, closely follow a...
Heights of 10 year olds. Heights of 10 year olds, regardless of gender, closely follow a normal distribution with mean 55 inches and standard deviation 6 inches. Round all answers to two decimal places. 1. What is the probability that a randomly chosen 10 year old is shorter than 67 inches? 2. What is the probability that a randomly chosen 10 year old is between 60 and 63 inches? 3. If the tallest 15% of the class is considered very...
Among 33 - to 38 -year-olds, 31 % say they have called a talk show while...
Among 33 - to 38 -year-olds, 31 % say they have called a talk show while under the influence of peer pressure . Suppose seven 33 - to 38 -year-olds are selected at random. (a) What is the probability that at least one has not called a talk show while under the influence of peer pressure ? (b) What is the probability that at least one has called nbsp a talk showwhile under the influence of peer pressure ? (a)...
Please write neatly ? Problem 4 Four-year-olds in China average 5 unsupervised hours per day. Most...
Please write neatly ?
Problem 4 Four-year-olds in China average 5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1 A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or...
A) 3.10 Heights of 10 year olds: Heights of 10 year olds, regardless of gender, closely...
A) 3.10 Heights of 10 year olds: Heights of 10 year olds, regardless of gender, closely follow a normal distribution with mean 55 inches and standard deviation 6 inches. What is the probability that a randomly chosen 10 year old is between 60 and 65 inches? (please round to four decimal places) B) In analyzing hits by bombs in a past war, a city was subdivided into 617 regions, each with an area of 0.5-mi². A total of 475 bombs...
According to a publication, 14.7 % of 18 to 25-year-olds were users of marijuana in 2000....
According to a publication, 14.7 % of 18 to 25-year-olds were users of marijuana in 2000. A recent poll of 1228 randomly selected 18 to 25-year-olds revealed that 215 currently use marjuana. At the 5 % significance level, do the data provide sufficient evidence to conclude that the percentage of 18 to 25-year-olds who currently use marijuana has changed from the 2000 peroentage of 14.7 % ? Use the one-proportion z-test to perform the appropriate hypothesis test, after checking the...
Four-year-olds in China average 3.5 unsupervised hours per day. Most of the unsupervised children live in...
Four-year-olds in China average 3.5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1 . A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or a decimal value accurate to...
The daily exchange rates for the five-year period 2003 to 2008 between currency A and currency...
The daily exchange rates for the five-year period 2003 to 2008 between currency A and currency B are well modeled by a normal distribution with mean 1.466 in currency A (to currency B) and standard deviation 0.041 in currency A. Given this model, and using the 68-95-99.7 rule to approximate the probabilities rather than using technology to find the values more precisely, complete parts (a) through (d). a) What is the probability that on a randomly selected day during this...
Problem 4 Four year-olds in China average 5 unsupervised hours per day. Most of the unsupervised...
Problem 4 Four year-olds in China average 5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1. A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or a decimal value...
The amount y (in billions of dollars) of income taken in by a certain country's social...
The amount y (in billions of dollars) of income taken in by a certain country's social security administration for old-age and survivor's insurance in year x can be approximated by the equation below. 111.7(x - 2010) = 7y - 3742.22 Assuming the trend continues, find the year in which 773.96 billion dollars will be taken in. What is the value of y? y=1 (Type an integer or a decimal. Do not include the $ symbol in your answer.)
Please write neatly ?
Problem 4 Four-year-olds in China average 5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1 A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or...
According to a publication, 14.7 % of 18 to 25-year-olds were users of marijuana in 2000. A recent poll of 1228 randomly selected 18 to 25-year-olds revealed that 215 currently use marjuana. At the 5 % significance level, do the data provide sufficient evidence to conclude that the percentage of 18 to 25-year-olds who currently use marijuana has changed from the 2000 peroentage of 14.7 % ? Use the one-proportion z-test to perform the appropriate hypothesis test, after checking the...
Four-year-olds in China average 3.5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1 . A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or a decimal value accurate to...
Problem 4 Four year-olds in China average 5 unsupervised hours per day. Most of the unsupervised children live in rural areas, considered safe. Suppose that the amount of unsupervised time is normally distributed with standard deviation 1. A Chinese 4-year-old is randomly selected from a rural area. We are interested in the amount of time the child spends alone per day. In each appropriate box you are to enter either a rational number in "p/q" format or a decimal value...
The amount y (in billions of dollars) of income taken in by a certain country's social security administration for old-age and survivor's insurance in year x can be approximated by the equation below. 111.7(x - 2010) = 7y - 3742.22 Assuming the trend continues, find the year in which 773.96 billion dollars will be taken in. What is the value of y? y=1 (Type an integer or a decimal. Do not include the $ symbol in your answer.)
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