Question

The electric field produced by a 2.90 C point charge at a distance of 1.0 m is 2.6 × 104 (N/C). Now, let’s put another charge q0 (2.00 C) at this region. Which explanation is correct? Choose the best answer. a. Since it has a positive charge, the direction of electric field is away from it (outbound). b. The potential generated by this charge has a positive value. c. If the q0 is moved by 0.02 m along the equipotential line, the work done is 0 (zero). d. All of the above.

Answer 1

(d) All of the above

(a) The direction of electric field lines from positive to negative charges,it is correct.

(b) potential(V)=kq/r

if charge is positive then potential is also positive value.

(c) work done(W)=qxdv

so change in potential is zero in equipotential surface then work done is zero