Question

 You measure an electric field of 1.39x10° N/C at a distance of 0.154 m from a point charge. There is no other source of electric field in the region other than this point charge.

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Part A

 What is the electric flux through the surface of a sphere that has this charge at its center and that has radius 0.154 m?

 Part B

 What is the magnitude of the charge?

Answer 1

Solution :-

A. Electric flux = (phi) = EA cos theta

where E is Electric fiels

A is area = 4 pi r^2

so here flux phi = 1.39×10^6×4×3.14× 0.154*0.154

flux phi = 4.1404×10^5 Nm^2/C
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apply Gauss LAw, flux   = q/eo

so charge q = 4.1404×10^5 * 8.85×10^-12

q = 3.66×10^-6 C