Hexane is a common laboratory solvent and a component of petrol. Its combustion reaction is as...
Hexane is a common laboratory solvent and a component of petrol. Its combustion reaction is as follows: 2 C6H14 (g) + 19 O2(g) ⟶ 12 CO2(g) + 14 H2O(l) Δ rHo = -8326 kJ mol-1 Use the reaction enthalpy value to calculate the heat in (kJ mol-1) released by combustion of 0.138 mol of hexane.
Homework Answers
2 C6H14 (g) + 19 O2(g) ⟶ 12 CO2(g) + 14 H2O(l) Δ rHo = -8326 kJ mol-1
moles of hexane = 0.138 mol
2 mol hexane -------------> -8326 kJ mol-1
0.138 mol hexane -----------> ??
heat released = 0.138 x 8326 / 2
= - 574.5 kJ/mol
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